why value of g is greater at pole ?

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why value of g is greater at pole ?

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https://byjus.com/question-answer/why-value-of-g-is-greater-at-pole

https://byjus.com/question-answer/why-value-of-g-is-greater-at-pole
Why is the value of g greater at the pole? – BYJU’S
The value of ‘g’ is greater at poles and lesser at equator of earth. Q. Why the value of g is more at the poles than at the equator of the earth? Q. Question 10. Amit buys few grams of gold at the poles as per the instruction of one of his friends. He hands over the same when he meets him at the equator. Will the friend agree with the …
Why gravitational force is more at poles and less at equator? – BYJU’S
This means that a body at the equator is farther away from the earth’s centre than a body at the poles. Therefore, the gravitational field at the equator will be lesser than that at the poles. that is, Sir Isaac newton discovered gravity and studied to give a formula : g=GM/r^2. What u r asking is the gravitational force i.e.
The value of ‘g’ is greater at poles and lesser at equator of earth.
Q. Earth is flattened at the poles and bulging at the equator. This is because: Q. Why the value of g is more at the poles than at the equator of the earth? when the gravity is at the center of the earth then the radius of the earth is same to the surface from core. then how is the force of gravity greater at the poles than at the equator?
The value of g at pole is – BYJU’S
greater than the value at the equator. Explanation. Earth is not a perfect sphere. It is flattened at the poles and bulged at the equator. The centrifugal force caused by the rotation of the earth results in the bulge of the earth at the equator.
Why the value of g is more at the poles than at the equator of … – BYJU’S
Q. Tell me why winds are deflected more at the poles than at the equator? Q. A man weighs 600 N on the equator, but when he moves to pole he finds a slight increase in his weight. This is because: Q. Why acceleration is greater at poles than the equator?? Why the value of g is more at the poles than at the equator of the earth?
Explain why the value of g differs while moving from poles to the …
Formula to calculate g at a place is given by g = GM R 2, where G is the Gravitational constant, M is the mass of earth, R is the distance from the center of the earth. Both G and M are constant. As, g α 1 R 2 which implies as the distance from the center of the earth increases, acceleration due to gravity decreases.

https://physics.stackexchange.com/questions/141856/why-is-earths-gravity-stronger-at-the-poles

https://physics.stackexchange.com/questions/141856/why-is-earths-gravity-stronger-at-the-poles
Why is Earth’s gravity stronger at the poles?
20. Many sources state that the Earth’s gravity is stronger at the poles than the equator for two reasons: The centrifugal force cancels out the gravitational force minimally, more so at the equator than at the poles. The poles are closer to the center due to the equatorial bulge, and thus have a stronger gravitational field.

https://pubs.aip.org / aapt / ajp / article / 46 / 8 / 790 / 1050955 / Why-is-g-larger-at-the-poles

https://pubs.aip.org / aapt / ajp / article / 46 / 8 / 790 / 1050955 / Why-is-g-larger-at-the-poles
Why is g larger at the poles? | American Journal of Physics | AIP …
Why is. g. larger at the poles? It is frequently stated that the value of the acceleration due to gravity at the pole is larger than at the equator because the poles are closer to the center of the earth due to the earth’s oblateness. This statement seems misleading in that it attributes significance to the center of mass in such …

https://www.physicsclassroom.com/class/circles/Lesson-3/The-Value-of-g

https://www.physicsclassroom.com/class/circles/Lesson-3/The-Value-of-g
The Value of g – The Physics Classroom
Its value is 9.8 m/s2 on Earth. That is to say, the acceleration of gravity on the surface of the earth at sea level is 9.8 m/s 2. When discussing the acceleration of gravity, it was mentioned that the value of g is dependent upon location. There are slight variations in the value of g about earth’s surface.

https://openstax.org/books/physics/pages/7-2-newtons-law-of-universal-gravitation-and-einsteins-theory-of-general-relativity

https://openstax.org/books/physics/pages/7-2-newtons-law-of-universal-gravitation-and-einsteins-theory-of-general-relativity
7.2 Newton’s Law of Universal Gravitation and Einstein’s … – OpenStax
This means the value of g varies from place to place in the universe. The relationship between force, mass, … Calculate Earth’s mass given that the acceleration due to gravity at the North Pole is 9.830 m/s 2 and the radius of the Earth is 6371 km from pole to center.

https://byjus.com/jee/acceleration-due-to-gravity

https://byjus.com/jee/acceleration-due-to-gravity
Acceleration due to Gravity – Value of g on Earth – BYJU’S
g′ = g – Rω 2 cos 2 θ. Where g′ is the apparent value of acceleration due to gravity at the latitude due to the rotation of the earth, and g is the true value of gravity at the latitude without considering the rotation of the earth. At poles, θ = 90°⇒ g’ = g. At the equator, θ = 0° ⇒ g′= g – Rω 2.

https://openstax.org/books/university-physics-volume-1/pages/13-2-gravitation-near-earths-surface

https://openstax.org/books/university-physics-volume-1/pages/13-2-gravitation-near-earths-surface
13.2 Gravitation Near Earth’s Surface – OpenStax
As soon as Cavendish determined the value of G in 1798, the mass of Earth could be calculated. (In fact, that was the ultimate purpose of Cavendish’s experiment in the first place.) The value we calculated for g of the Moon is incorrect. The average density of the Moon is actually only 3340 kg/m 3 3340 kg/m 3 and = 1.6 m/s 2 = 1.6 m/s 2 …

https://www.khanacademy.org/science/hs-physics/x215e29cb31244fa1:types-of-interactions/x215e29cb31244fa1:newton-s-law-of-universal-gravitation/v/viewing-g-as-the-value-of-earth-s-gravitational-field-near-the-surface

https://www.khanacademy.org/science/hs-physics/x215e29cb31244fa1:types-of-interactions/x215e29cb31244fa1:newton-s-law-of-universal-gravitation/v/viewing-g-as-the-value-of-earth-s-gravitational-field-near-the-surface
Viewing g as the value of Earth’s gravitational field near the surface …
The true value varies with your latitude and longitude (mainly due to surface variations in Earth’s density). g also varies with altitude according to the formula: g/g’ = (r’/r)^2, where g’ equals g at the Earth’s (or other celestial body’s surface) and r’ equals distance from the center of gravity of Earth (or other celestial body).

https://www.vedantu.com/question-answer/value-of-g-greater-at-the-poles-class-11-physics-cbse-60e08fac34a38468a5e98770

https://www.vedantu.com/question-answer/value-of-g-greater-at-the-poles-class-11-physics-cbse-60e08fac34a38468a5e98770
Why is the value of g greater at the poles? – Vedantu
28 mars 2024Formula for acceleration due to gravity is given by: g = GM R2 g = G M R 2. The value of the gravity at the pole is more significant than at the equator because the poles are nearer to the earth’s center due to the earth’s oblateness. This statement seems misleading in that it attributes significance to the center of mass in such situations and …

https://van.physics.illinois.edu/ask/listing/64061

https://van.physics.illinois.edu/ask/listing/64061
How Gravitational Force Varies at Different Locations on Earth
A: The variation in apparent gravitational acceleration (g) at different locations on Earth is caused by two things (as you implied). First, the Earth is not a perfect sphere—it’s slightly flattened at the poles and bulges out near the equator, so points near the equator are farther from the center of mass. The distance between the centers of …
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